2

I want to use a JSON_QUERY with a SELECT TOP 1 query such that the resultant json has that top 1 record in object form, instead of in table form?

For example, the following query (live demo):

CREATE TABLE Trees
(
    [Id] INT,
    [Type] NVARCHAR(100),
    [Height] DECIMAL(2,1)
);

INSERT INTO Trees ([Id], [Type], [Height]) VALUES (1, 'Palm', 5.5), (2, 'Pine', 6.2), (3, 'Apple', 2.5), (4, 'Japanese Cedar', 0.5), (5, 'Spanish Fir', 0.6);

SELECT highestTree = JSON_QUERY( ( SELECT TOP 1 Id as id, Type as type, Height as height FROM Trees WHERE Height = (SELECT Max(Height) FROM Trees) FOR JSON PATH ) ), lowestTree = JSON_QUERY( ( SELECT TOP 1 Id as id, Type as type, Height as height FROM Trees WHERE Height = (SELECT MIN(Height) FROM Trees) FOR JSON PATH ) ) FOR JSON PATH, WITHOUT_ARRAY_WRAPPER ;

outputs:

{"highestTree":[{"id":2,"type":"Pine","height":6.2}],"lowestTree":[{"id":4,"type":"Japanese Cedar","height":0.5}]}

But I want:

{"highestTree":{"id":2,"type":"Pine","height":6.2},"lowestTree":{"id":4,"type":"Japanese Cedar","height":0.5}}
Charlieface
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HeyJude
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1 Answers1

0

Try this one :


SELECT
  highestTree = JSON_QUERY(
      (
         SELECT TOP 1
         Id as id,
         Type as type,
         Height as height
         FROM Trees 
         WHERE Height = (SELECT Max(Height) FROM Trees)
         FOR JSON PATH,WITHOUT_ARRAY_WRAPPER
      )
  ),
  lowestTree = JSON_QUERY(
      (
         SELECT TOP 1
         Id as id,
         Type as type,
         Height as height
         FROM Trees 
         WHERE Height = (SELECT MIN(Height) FROM Trees)
         FOR JSON PATH,WITHOUT_ARRAY_WRAPPER
      )
 )
FOR JSON
  PATH, WITHOUT_ARRAY_WRAPPER
;

Result:

{"highestTree":{"id":2,"type":"Pine","height":6.2},"lowestTree":{"id":4,"type":"Japanese Cedar","height":0.5}}
Amirhossein
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