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Can anyone explain to me if there is the Early effect in MOS transistor then the Early effect affects the expression for VOV which is \$VOV=\sqrt{\frac{2ID}{kn'(W/L)}}\$?

M.Ferru
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elecV1
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    This is mentioned in any decent book about MOS transistors but anyway: The Early effect or Base-width modulation only happens in Bipolar transistors. In MOS transistors there is a similar effect (which I would never call Early effect) called Channel length modulation. It basically lowers the output impedance when the transistor is used as a current source. – Bimpelrekkie Jun 06 '17 at 14:43
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    Yes, its the $( 1 + \lambda V_{DS} )$ you see in the equation for drain current in saturation. – sstobbe Jun 06 '17 at 14:49
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    https://electronics.stackexchange.com/questions/298829/common-drain-jfet-output-resistance-problem/299030#299030 – G36 Jun 06 '17 at 14:56

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