D+GI vs D+D'GI, are they the sam term ? I even draw a true table for it. But how can we do it with boolean algebra? Adding a truth table.
Where D+GI is the POS from the table and D+D'GI is the SOP from the table. I believe they should be the same.
D+GI vs D+D'GI, are they the sam term ? I even draw a true table for it. But how can we do it with boolean algebra? Adding a truth table.
Where D+GI is the POS from the table and D+D'GI is the SOP from the table. I believe they should be the same.
D + GI
D + (D + D') GI
D + DGI + D'GI
D (1 + GI) + D'GI
D (1) + D'GI
D + D'GI
D (1 + GI) + D'GI step, if DGI simplifies to 1? You might as well remove it
– caird coinheringaahing
Sep 30 '21 at 18:30
A+A'B=A+B, but I consider the truth table to be a better proof on its own. – Justin Sep 30 '21 at 18:23