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Lets say i am using a counterweight and a weight on the other end of an arm (that i want to launch like a trebuchet)- im not sure how to find the formula between the range of motion and the weight (and angle of launch): this is what i tried-

$$Ek=Ep \text{(energy converted from potential to kinetic of weight)}$$ $$\frac{mv^2}{2}=mgh, v= \sqrt{2gh}$$

Then i used $Range= v^2\frac{\sin(2\theta)}{g}$ to find range but i keep getting really weird answers- where am i going wrong with this please?

NMech
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Johnny
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1 Answers1

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There is a detailed explanation on "Real-world-physics-problems.com".

Here is the Link, trebuchet

kamran
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