-1

This question might be better suited for this stack. In the physics stack, I posted about a question about siphoning. https://physics.stackexchange.com/q/677102/259268

An 10 meter tall cylinder is sitting in a infinite pool of water. It has supports on the bottom attached to the base of the pool to maintain its vertical position. The top of the cylinder is closed and the bottom is open to the water. The bottom of the cylinder is not exposed to air and is submerged. There is a hose located 1 meter below the top of the cylinder which leads through the wall of the cylinder. The hose entrance is at a higher elevation (~9 m) than the hose exit (~8 m). Currently the hose exit is closed.

Water fills the cylinder and hose combination (the air is released, there is no air in the entire setup, only water). The atmospheric pressure outside the cylinder(and hose) and the properties of water allows for the 10 meter height of the water column. Suddenly the hose exit opens, starting the siphon process. Water drops 8 meters into a water turbine sitting level with the surface of the pool. Beneath the turbine is just an extension of the pool that the cylinder also occupies.

As the water falls from the hose exit, it starts pulling water from the top of the cylinder. The open bottom of the cylinder starts pulling water from the pool. The water goes through the turbine and re-enters the pool. The flow of water through the cylinder is continuous as it can not drain the entire pool of water.

Siphon

3 Answers3

2

Siphons are limited by atmospheric pressure.

The exact why of this is a bit complicated, and the statement isn't quite correct, but we are right at the limit. Other factors are the liquid's vapor pressure, its characteristics, and the tube itself.

A 10 meter siphon must overcome the weight of 10 m of water.

We'll do this in both SI & Imperial units.

10m water = .098 MPa. Just under atmospheric at sea level

393.7 in water = 14.2 psi

Tiger Guy
  • 7,376
  • 10
  • 22
0

enter image description here

A diagram in your question would be a big help. I think you are describing (a) above.

If you open the valve at the end of the hose at the 9 m level the weight of the 10 m water column will collapse the water column into the tank and suck all the water out of the hose as fast as the air can flow through the hose.

For a siphon to work the outlet must be below the level of the water exposed to atmospheric pressure - the surface of your tank in this case.

enter image description here

Note that your cylinder doesn't make any difference to just using a hose as shown in (b). The ΔP (delta-P / difference in pressure) between the tank surface and the pipe outlet will be the same regardless of the diameter of the column.

Transistor
  • 12,108
  • 2
  • 22
  • 32
0

The sketch is to help you to clear up your question. You should identify where the hose is terminated - (a) or (b)? Please feel free to copy and edit the sketch to match your thought.

enter image description here

Two Example Cases:

enter image description hereenter image description here

https://en.wikipedia.org/wiki/Siphon

r13
  • 8,333
  • 3
  • 10
  • 29