Does the speed of the water flowing radially outwards from a water jet impacting a sink depend on how far the tap is opened?
At the moment, I understand that the maximum velocity of the water in the vertical jet is constant regardless of how far the tap is open (as it is accelerated by gravity, and disregarding air-resistance), but the volume flow rate is greater the further the tap is opened.
I'm thinking that a higher volume flow rate results in a greater depth around the bottom of the jet which reduces the effect of friction between the water and the sink as the contact surface of the water has reduced, which would decelerate the water at a lower rate than if it were shallower, but am not sure.
Could someone explain precisely how opening a tap affects the radial speed of the water around the bottom of the jet?
EDIT
I should have clarified that, for my question, the area is variable. What I had in mind was more like a variably sized circular hole beneath a constant-height water tank. I used the word "tap" for simplicity, but I realise now this is a bad substitute, and has caused more confusion than intended.