How do I kill processes older than "t"?

Question

First, yes I have seen this question:

The answers there are incorrect and do not work. I have voted and commented accordingly.

The processes I want to kill look like this when listed with ps aux | grep page.py:

apache     424  0.0  0.1   6996  4564 ?        S    07:02   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache    2686  0.0  0.1   7000  3460 ?        S    Sep10   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache    2926  0.0  0.0   6996  1404 ?        S    Sep02   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache    7398  0.0  0.0   6996  1400 ?        S    Sep01   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache    9423  0.0  0.1   6996  3824 ?        S    Sep10   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache   11022  0.0  0.0   7004  1400 ?        S    Sep01   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache   15343  0.0  0.1   7004  3788 ?        S    Sep09   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache   15364  0.0  0.1   7004  3792 ?        S    Sep09   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache   15397  0.0  0.1   6996  3788 ?        S    Sep09   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache   16817  0.0  0.1   7000  3788 ?        S    Sep09   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache   17590  0.0  0.0   7000  1432 ?        S    Sep07   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache   24448  0.0  0.0   7000  1432 ?        S    Sep07   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py
apache   30361  0.0  0.1   6996  3776 ?        S    Sep09   0:00 /usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py

I'm looking to setup a simple daily cron that will find and kill any page.py processes older than an hour.

The accepted answer on the aforementioned question does not work, as it doesn't match a range of times, it simply matches processes that have been running from 7 days to 7 days 23 hours 59 minutes and 59 seconds. I don't want to kill processes that have been running from 1-2 hours, but rather anything greater than 1 hour.

The other answer to the aforementioned question using find does not work, at least not on Gentoo or CentOS 5.4, it either spits out a warning, or returns nothing if the advice of said warning is followed.

score 27 · Answer 1 · answered May 29 '12 at 03:11

27

GNU Killall can kill processes older than a given age, using their processname.

if [[ "$(uname)" = "Linux" ]];then killall --older-than 1h page.py;fi

answered May 29 '12 at 03:11

Jodie C

743

eugenevd · Answer 2 · 2019-09-30T10:54:10.303

find doesnt always work, not every system has etimes available, and it might be my regex newb status, but I dont think you need anything more than this:

ps -eo pid,etimes,comm,user,tty | awk '{if ($4 ~ /builder/ && $5 ~ /pts/ && $2>600) print $1}'

list all processes and provide columns PID,ELAPSED(etimes = seconds), COMMAND, USER, TT (thanks @ahoffman)
with awk print the PID where the 4th column ($4, USER) contains text 'builder', and 5th column ($5, TT) contains text 'pts' and the ELAPSED column has a value larger than 600 sec (thanks @amtd)

you can then pipe that to kill or whatever your need may be.

score 10 · Accepted Answer · answered Sep 15 '10 at 18:10

Thanks to Christopher's answer I was able to adapt it to the following:

find /proc -maxdepth 1 -user apache -type d -mmin +60 -exec basename {} \; \
| xargs ps | grep page.py | awk '{ print $1 }' | sudo xargs kill

-mmin was the find command I was missing.

poige · Answer 4 · 2016-11-12T18:11:07.323

6

# get elapsed time in seconds, filter our only those who >= 3600 sec
ps axh -O etimes  | awk '{if ($2 >= 3600) print $2}'

If you want you can feed ps with list of PIDs to lookup within, for e. g.:

ps h -O etimes 1 2 3

edited Nov 12 '16 at 18:11

answered May 29 '12 at 06:20

poige

9,730
3
28
53

Christopher Karel · Answer 5 · 2010-09-15T18:00:19.890

I think you can modify some of those previous answers to fit your needs. Namely:

for FILE in (find . -maxdepth 1 -user processuser -type d -mmin +60)
  do kill -9 $(basename $FILE) # I can never get basename to work with find's exec.  Let me know if you know how!
done

Or

ps -eo pid,etime,comm | awk '$2!~/^..:..$/ && $3~/page\.py/ { print $1}' | kill -9

I think the second may best fit your needs. The find version would wind up nuking other processes by that user

--Christopher Karel

score 4 · Answer 6 · edited Mar 31 '16 at 15:28

4

apt-get install psmisc

killall -o 1h $proc_name

edited Mar 31 '16 at 15:28

Nixphoe

4,624

answered Mar 30 '16 at 22:58

Alex

51

score 4 · Answer 7 · answered Nov 12 '16 at 10:19

The problem

Converting etime (elapsed time) column of ps command to seconds. The time specification is in this format [[dd-]hh:]mm:ss. Newer versions of ps have an etimes column which outputs etime value in seconds.

The solution: simple custom awk function

This custom awk function supports all formats of etime column (e.g. 03-12:30:59, 00:07 etc.). Just paste it in your awk script, it is one-liners friendly solution.

function sec(T){C=split(T,A,"[:-]"); return A[C>3?C-3:99]*86400 + A[C>2?C-2:99]*3600 + A[C>1?C-1:99]*60 + A[C>0?C-0:99]*1}

sec(T) converts T to seconds
T time specification in [[dd-]hh:]mm:ss format (e.g. etime)
C count of fields in T (equivalent to awk's NF variable)
A array of fields in T (equivalent to awk's $ variable)
A[C>3?C-3:99] this is safe way to reference the fourth value (i.e. number of days) in reverse order. This approach is useful because days and hours are optional. If the array is not long enough it dereference A[99] which will yield 0 value. I assume 99 is high enough for most use cases.
returns seconds as integer

Real world example

This bash oneliner will kill soffice.bin process running under current user if the process is older than 180 seconds.

kill -9 $(ps cx -o command,etime,pid | awk '/^soffice.bin/ {if (sec($2)>180) {print $3}} function sec(T){C=split(T,A,"[:-]"); return A[C>3?C-3:99]*86400 + A[C>2?C-2:99]*3600 + A[C>1?C-1:99]*60 + A[C>0?C-0:99]*1}')

score 1 · Answer 8 · edited Feb 14 '12 at 19:24

The lstart field in ps gives a consistent time format which we can feed to date to convert to seconds since the epoch. Then we just compare that to the current time.

#!/bin/bash
current_time=$(date +%s)
ps axo lstart=,pid=,cmd= |
    grep page.py |
    while read line
    do
        # 60 * 60 is one hour, multiply additional or different factors for other thresholds 
        if (( $(date -d "${line:0:25}" +%s) < current_time - 60 * 60 ))
        then
            echo $line | cut -d ' ' -f 6    # change echo to kill
        fi
    done

score 1 · Answer 9 · answered Oct 12 '15 at 13:42

1

this should work

killall --older-than 1h $proc_name

answered Oct 12 '15 at 13:42

Jabir Ahmed

39

score 0 · Answer 10 · answered Sep 15 '10 at 18:01

I modified the answer they gave you in previous post

ps -eo pid,etime,comm | 
egrep '^ *[0-9]+ +([0-9]+-[^ ]*|[0-9]{2}:[0-9]{2}:[0-9]{2}) +/usr/bin/python2.6 /u/apps/pysnpp/current/bin/page.py' | 
awk '{print $1}' | 
xargs kill

The regular expression searches for 2 types of second argument:

Days in the form of digits and a minus sign.
Hours:minutes:seconds expression.

That should match everything except young processes who would have the form minutes:seconds.

score 0 · Answer 11 · answered Sep 15 '10 at 18:33

This is probably overkill, but I got curious enough to finish it and test that it works (on a different process name on my system, of course). You can kill the capturing of $user and $pid to simplify the regexp, which I only added for debugging, and didn't feel like ripping back out. Named captures from perl 5.10 would shave off a couple more lines, but this should work on older perls.

You'll need to replace the print with a kill, of course, but I wasn't about to actually kill anything on my own system.

#!/usr/bin/perl -T
use strict; use warnings;

$ENV{"PATH"} = "/usr/bin:/bin";                                                       

my (undef,undef,$hour) = localtime(time);                                             
my $target = $hour - 2; # Flag process before this hour                               
my $grep = 'page.py';                                                   

my @proclist = `ps -ef | grep $grep`;                                                 
foreach my $proc (@proclist)                                                          
{                                                                                     
    $proc =~ /(\w+)\s+(\d+)\s+\d+\s+\d+\s+(.*?).*/;                   
    my $user = $1;                                                                    
    my $pid = $2;                                                                     
    my $stime = $3;                                                                   

    $stime =~ s/(\d+):(\d+)/$1/;                                                      

    # We're going to do a numeric compare against strings that                        
    # potentially compare things like 'Aug01' when the STIME is old                   
    # enough.  We don't care, and we want to catch those old pids, so                 
    # we just turn the warnings off inside this foreach.                              
    no warnings 'numeric';                                                            

    unless ($stime > $target)                                                         
    {                                                                                 
        print "$pid\n";                                                               
    }                                                                                 
}

score 0 · Answer 12 · answered Aug 10 '11 at 13:42

I have a server with wrong dates in /proc and find doesn't work so I wrote this script:

#!/bin/bash

MAX_DAYS=7  #set the max days you want here
MAX_TIME=$(( $(date +'%s') - $((60*60*24*$MAX_DAYS)) ))

function search_and_destroy()
{
        PATTERN=$1
        for p in $(ps ux|grep "$PATTERN"|grep -v grep| awk '{ print $2 }')
        do
            test $(( $MAX_TIME - $(date -d "`ps -p $p -o lstart=`" +'%s') )) -ge 0 && kill -9 $p
        done
}

search_and_destroy " command1 "
search_and_destroy " command2 "

score 0 · Answer 13 · answered Aug 10 '11 at 14:07

Python version using the ctime of the process entries in /proc:

#!/usr/bin/env python
# -*- coding: utf-8 -*-
# kills processes older than HOURS_DELTA hours

import os, time

SIGNAL=15
HOURS_DELTA=1

pids = [int(pid) for pid in os.listdir('/proc') if pid.isdigit()]

for pid in pids:
    if os.stat(os.path.join('/proc', str(pid))).st_ctime < time.time() - HOURS_DELTA * 3600:
        try:
            os.kill(pid, SIGNAL)
        except:
            print "Couldn't kill process %d" % pid

score 0 · Answer 14 · answered Sep 12 '13 at 16:21

I use this simple script it takes two arguments name of process and age in seconds.

#!/bin/bash
# first argument name of the process to check
# second argument maximum age in seconds
# i.e kill lighttpd after 5 minutes
#   script.sh lighttpd 300 
process=$1
maximum_runtime=$2
pid=`pgrep $process`
if [ $? -ne 0 ]
then
        exit 0
fi
process_start_time=`stat /proc/$pid/cmdline --printf '%X'`
current_time=`date +%s`
let diff=$current_time-$process_start_time

if [ $diff -gt $maximum_runtime ]
then
        kill -3 $pid
fi

score 0 · Answer 15 · answered Feb 25 '17 at 12:27

I was not satisfied with the other solution, most of them are too cryptic ( my bash knowledge is kind of limited) and so I cannot customize them ...
I have created my own solution, It is probably not the best but it works and it is readable

You can save this script in a file and make it executable ( eventually call it with using cron )

#!/bin/bash
## time in second that trigger the kill
LIMIT=10
## [] skip the grep from the process list
PROC_NAME="[m]y process name"
## etimes return the time in seconds
TIME_SEC=$(ps axo etimes,pid,command | grep "$PROC_NAME" | awk {'print$1'})
PID=$(ps axo etimes,pid,command | grep "$PROC_NAME" | awk {'print$2'})

if [ -n "$TIME_SEC" ] 
    then
    if (( $TIME_SEC > $LIMIT )); then
        kill $PID
    fi
fi

score -2 · Answer 16 · edited Apr 25 '15 at 06:44

-2

72=3days 48=2days 24=1day

a1=$(TZ=72 date +%d) ps -ef| cat filex.txt | sed '/[JFMASOND][aepuco][nbrylgptvc] '$a1'/!d' | awk '{ print $2 " " $5 " " $6 }' > file2.txt

it works :)

edited Apr 25 '15 at 06:44

MadHatter

81,580

answered Apr 25 '15 at 06:28

onkar

1

How do I kill processes older than "t"?

16 Answers16

The problem

The solution: simple custom awk function

Real world example

Linked