How can I replace line #6 in a text file in a bash script?

Question

I have a text file that is generated by 3rd-party software as part of a build process. I want to replace one specific line - in my case, line 6. How can I do this in my bash script?

I suspect sed is my friend here but I'm now stumped.

I'm using Mac OS X 10.6 if that's important.

score 9 · Accepted Answer · answered Sep 17 '10 at 12:14

9

Try sed "6s/old/new/g" file.txt

answered Sep 17 '10 at 12:14

weeheavy

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How can I replace line #6 in a text file in a bash script?

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