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I have been given the following IP 192.168.14.137/25 and asked to divide the network into 2.

This is what I've come up with:

  • The subnet mask is 255.255.255.128
  • The network address is 192.168.14.128

There are a total of 128 available addresses (including the network address and broadcast address)

To divide the network we create two subnets:

  • 192.168.14.128/26
  • 192.168.14.192/26

This will have a subnet mask of 255.255.255.192

Am I missing anything, or is this correct?

Starfish
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kylex
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1 Answers1

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Yes, everything is correct in your calculations.

Serge
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